Question

Given 3 consecutive positive integers, the product of the smaller integers is nine times the larger integer plus 2. What is the value of the integer closest to zero?

          Given 3 consecutive positive integers, the product of the smaller integers is nine times the larger integer plus 2. What is the value of the integer closest to zero?
        

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Given 3 consecutive positive integers, the product of the smaller integers is nine times the larger integer plus 2. What is the value of the integer closest to zero?
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Transcript

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00:01 Okay, we have here then three consecutive integers.
00:04 So that means in general, like 5, 6, 7, 10, 11, 12.
00:10 It could be x is the first one, x plus 1 is the next, and then x plus 2 is the third.
00:19 Those three numbers are consecutive.
00:24 We are told that the product of that, so if i multiply x by xx, plus 1 by x plus 2 what i will get is the middle number which is x plus 1.
00:39 So that equation if i try and solve it i can divide both sides by x plus 1.
00:48 So i divide here by x plus 1 and divide here by x plus 1.
00:56 And on the left i just get x times x plus 2.
01:01 On the right i get just 1.
01:06 So this becomes x squared plus 2x minus 1 equals 0 if i rearrange it.
01:16 So expand out and rearrange...
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