Given a 6 b 7 c 6 d 6 e 6 and f 5 in the figure below use...

Given a = 6, b = 7, c = 6, d = 6, e = 6 and f = 5, in the figure below, use superposition to calculate: • Contribution of the current source in $I_O$ (in mA): • Contribution of the voltage source in $I_O$ (in mA): c k$\Omega$ b k$\Omega$ d k$\Omega$ a V f mA e k$\Omega$ $I_O$

Transcript

00:01 Okay, we're supposed to find the unknown current i 0 this circuit using superposition okay, so the superposition method basically says we've got three different power sources here.

00:16 We've got a 12 volt dc voltage source we've got a 6 milliampere current source here and a 4 milliampere current source down here okay, the way superposition works is we work with one current source at a time and then we figure out what the currents are for that current source or that voltage source and then we add them all together for that whatever branch of the circuit we're interested in.

00:47 Okay, and the way we do it is when we whenever we whatever we ignore a current source we ignore the entire branch that it's part of and when we ignore a voltage source we make it a short circuit is the general rule okay, so we have to actually calculate three.

01:18 We have to calculate i 0 for three different circuits so let's go for the voltage source first so here's what that circuits gonna look like.

02:10 Okay, and then my i 0 let's call it i 0 a is here.

02:21 All right so we can get we can just look at that loop in that lower right hand corner okay, and we get the following equation 12 volts minus 4k plus 2k and we're going opposite to error.

02:47 So it's actually plus equals zero so i 0 a is minus 12 volts.

03:02 Oh, that's 2 not 12.

03:16 It's minus 12 volt over 6k it's minus 2 milliamperes okay, we don't have to worry about the top branch because we're only interested in the current i 0 so that's with both current sources crossed out remember i said when you cross out a current source leave out the entire branch of the circuit that has that current source in it we leave out the voltage source you make it into a short circuit okay, then for the remaining one...

Question

Given a = 6, b = 7, c = 6, d = 6, e = 6 and f = 5, in the figure below, use superposition to calculate: • Contribution of the current source in $I_O$ (in mA): • Contribution of the voltage source in $I_O$ (in mA): c k$\Omega$ b k$\Omega$ d k$\Omega$ a V f mA e k$\Omega$ $I_O$

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