00:01
In this problem, we are given that there is a back, and this consists of 10 balls which are red, 30 of them are white balls, and 20 are black balls, and 15 of them are yellow balls.
00:14
And out of this back, two balls are drawn.
00:18
And when we draw these two balls, we draw in succession with replacement, and we are required to get the probability that one ball is red.
00:31
So only one is red, its probability we have to figure out.
00:36
So let's consider e as the event of drawing two balls out of the bag such that one is red ball.
00:49
So in this case, we see that the number of outcomes, which would be favorable to this event e.
00:55
Let's represent that with an e.
00:57
This would be equal to 10 c1 into the possible...