00:01
So having this question, firstly, the cross -section area of the pipe can be calculated as is equal to pi, d by two whole square, and that is equal to pi, diameter is 0 .05 by two whole square, and that is 0 .001963 meter square.
00:21
Then we calculate the change in pressure in the system, since both tanks are open to the atmosphere and there is no change in height, the change in pressure is due to the head loss of the system, the head loss can be calculated using the formula hf, and that is equals to f into l by t into v square by 2g, plus the sum of le by d into v square by 2g, where f is the friction factor, l is the length of the pipe, d is the diameter, v's velocity, g is the acceleration due to gravity, and le by d are the equivalent length of the fittings.
00:58
The total equivalent length of the pittings is 7 into 1, 7 into 1 plus 4 into 15, that is 67, which is dimensionless.
01:09
The total head loss, that is, hf, is 0 .015 into 190 by 0 .05 plus 67 into v.
01:22
V squared by 2 into 9 .81...