00:01
Let's try to find out the ph for the first part.
00:03
We can write it for the solution h plus is equal to 6 .6 multiplied 10 raised to minus 4m.
00:12
Taking the negative of the logarithm on the both the side, we're getting ph is equal to minus log h plus is equal to minus log 6 .6 multiplied 10 raised to minus 4.
00:28
So the ph will become minus log 6 .6 minus log 10 raised to minus 4.
00:37
The ph value we are going to get it after applying the log over here.
00:42
What we used to get it that the ph is equal to 3 .18.
00:48
This is a required solution for the first part.
00:50
Moving ahead, we can write it here for the next second for h plus.
01:00
We are knowing that this is 6 .6 multiplied 10 raised to minus 4m.
01:04
Hydride ion of the concentration is being given by h plus multiplied oh minus here is equal to kw.
01:14
So the oh minus is equal to 10 raised to minus 4 divided 6 .6 multiplied 10 raised to minus 4...