Question

Given a normal distribution with μ = 87 and σ = 2.8, find (8 points) A) the normal curve area (probability) for x >=76.4 B) the normal curve area (probability) between x = 81.2 and x = 88 (C) the normal curve area (probability) between x = 79.6 and x = 90.4

          Given a normal distribution with μ = 87 and σ = 2.8, find (8 points)
A) the normal curve area (probability) for x >=76.4
B) the normal curve area (probability) between x = 81.2 and x = 88
(C) the normal curve area (probability) between x = 79.6 and x = 90.4
        
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Added by Nicole P.

Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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Given a normal distribution with μ = 87 and σ = 2.8, find (8 points) A) the normal curve area (probability) for x >=76.4 B) the normal curve area (probability) between x = 81.2 and x = 88 (C) the normal curve area (probability) between x = 79.6 and x = 90.4
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Transcript

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00:02 In this question, for part a, here we have what? here we have z is equals to x minus mu divided by sigma.
00:12 So, this value is equals to what? so, this value is equals to 58 minus 55 divided by sigma divided by 7.
00:21 So, this is equals to 3 divided by 7.
00:22 So, here the value is what? here the value is 0 .43.
00:28 Now, so we draw the graph for this.
00:32 So, here we have points 34, then 41, then 48, then we have 55, then we have 62, then 69, then 76, okay.
00:54 So, the graph will rise from here from 34 and it will rise at peak here over here, okay and it go up to 76.
01:03 So, we have shaded region between this, okay.
01:08 Within this part, we have the shaded region.
01:10 So, here t, that is probability for x is greater than 58.
01:18 This is equivalent to what? this is equivalent to or equal to we can say probability that is z is greater than what? z is greater than 0 .43.
01:31 So, here this value is equals to what? so, this value is equals to we have 0 .3341.
01:37 Now, we solve for the part b.
01:40 So, in part b here, what we have? we have z is equals to x minus mu divided by what? divided by sigma.
01:50 So, this value is equals to what? so, this value is equals to 43 minus 55 whole divided by what? whole divided by 7.
01:58 So, this value is equals to what? so, this value is equals to minus 12 divided by 7.
02:02 So, this is equals to what? so, this is equals to we have minus 1 .71.
02:09 Now, we draw the graph for this.
02:14 So, here the graph is like we have this similarly as a previous one, but the shaded region will change, okay.
02:21 So, here we have 34, then we have 41, then we have 48, then 55, okay, then we have here 62, then 69 and then 76, okay.
02:43 Similarly, in the previous one, it will be at peak at what? it will be at peak when it is it reached to 55.
02:50 So, it will move from here and peak at this point and it's go up to 76.
02:54 So, here we have a shaded region from this region to this region, because we have to find the what? we have to find the probability that is x is greater than 43.
03:07 So, this is equals to p for z is greater than what? z is greater than minus 1 .71.
03:13 So, this value is equals to we have 0 .9568...
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