Question

Given a shell and tube heat exchanger with a heat transfer fluid on the inner tube with a heat transfer coefficient h1 = 30 W/(m2 K) and a fluid on the outer side of the tube with heat transfer coefficient of h2 = 55 W/(m2 K ). The tube is made of stainless steel with a thermal conductivity of 43 W/ mK. Assume the area of heat exchange is the same throughout the exchanger of 100 cm2 and calculate the overall heat transfer coefficient of U. You may ignore the effects of fouling.

          Given a shell and tube heat exchanger with a heat transfer fluid on the inner tube with a heat transfer coefficient h1 = 30 W/(m2 K) and a fluid on the outer side of the tube with heat transfer coefficient of h2 = 55 W/(m2 K ). The tube is made of stainless steel with a thermal conductivity of 43 W/ mK. Assume the area of heat exchange is the same throughout the exchanger of 100 cm2 and calculate the overall heat transfer coefficient of U. You may ignore the effects of fouling.
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Given a shell and tube heat exchanger with a heat transfer fluid on the inner tube with a heat transfer coefficient h1 = 30 W/(m2 K) and a fluid on the outer side of the tube with heat transfer coefficient of h2 = 55 W/(m2 K ). The tube is made of stainless steel with a thermal conductivity of 43 W/ mK. Assume the area of heat exchange is the same throughout the exchanger of 100 cm2 and calculate the overall heat transfer coefficient of U. You may ignore the effects of fouling.
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Transcript

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00:01 Here we know that heat transfer that is q is equal to m into cp into temperature out minus temperature in.
00:15 So we will calculate the heat transfer of water and ethylene glass for water.
00:24 It will be equal to 0 .8 into 4180 into 70 minus 22 which will be equal to 16150.
00:46 Now for glycol it will be is equal to mask glycol into 2680 into 110 minus 60 degree celsius.
01:06 So mass of glycol can be calculated as q upon glycol upon 2680 into 50.
01:21 Since heat transfer is same in the case of water and glycol so we can write q of glycol as 16150 upon 2680 into 50 which will be equal to 1 .2 kg...
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