Given a triangle ABC, a = 12, b = 21, c = 32, find the measure of \( \angle C \) to the nearest tenth of a degree.
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The law of cosines states that c^2 = a^2 + b^2 - 2ab*cos(C). Plugging in the given values, we get: 32^2 = 12^2 + 21^2 - 2*12*21*cos(C) 1024 = 144 + 441 - 504*cos(C) 1024 = 585 - 504*cos(C) 504*cos(C) = 585 - 1024 504*cos(C) = -439 cos(C) = -439/504 C = Show more…
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