Question

Given $A_1, A_2, A_3$ are fixed constant, and $A_n = A_{n-1} + A_{n-2} + A_{n-3}$ \newline $n \in N$, and $n \ge 4$. If $A_n = \alpha A_1 + \beta A_2 + \gamma A_3$, then $(\alpha, \beta, \gamma)$?

Name: Given A1, A2, A3 are fixed constant, and An = An-1 + An-2 + An-3 n ∈ N, and n ≥ 4. If An = α A1 + β A2 + γ A3, then (α, β, γ)?
Uploaded: 2022-03-04T13:28:48-08:00
Duration: 3 min 14 s
Channel: Ankit Singh
Description: Given A1, A2, A3 are fixed constant, and An = An-1 + An-2 + An-3 n ∈ N, and n ≥ 4. If An = α A1 + β A2 + γ A3, then (α, β, γ)?

          Given $A_1, A_2, A_3$ are fixed constant, and $A_n = A_{n-1} + A_{n-2} + A_{n-3}$ \newline $n \in N$, and $n \ge 4$. If $A_n = \alpha A_1 + \beta A_2 + \gamma A_3$, then $(\alpha, \beta, \gamma)$?

Added by Eva Q.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Ankit Singh

03/04/2022

Step 1

Step 1: We can write the first few terms of the sequence: $A_4 = A_3 + A_2 tan^{-1}s$ $A_5 = A_4 + A_3 tan^{-1}s = A_3 + A_2 tan^{-1}s + A_3 tan^{-1}s = A_3(1 + tan^{-1}s) + A_2 tan^{-1}s$ $A_6 = A_5 + A_4 tan^{-1}s = A_3(1 + tan^{-1}s) + A_2 tan^{-1}s + (A_3 + A_2 Show more…

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Given $A_1$, $A_2$, $A_3$ are fixed constants, and $A_n = A_{n-1} + A_{n-2} tan^{-1}s$ $n \in N$, and $n \ge 4$. If $A_n = xA_1 + \beta A_2 + \gamma A_3$, then $(x, \beta, \gamma)$?