Given an npn BJT operating in active region, if VBE = 0.65 V and VCB = 8.2 V, IE = 4 mA and IC/I

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Sri K · Answer

In this question we have the value of current i s which is equal to 1 pique ampere then we have

Deepak Jangra · Answer

Hey everyone in this portion we have been given a PNP transistor okay a PNP transistor and for t

Ajay Singhal · Answer

Hello students in this question we have given that a transistor operating in the common base con

Varsha Aggarwal · Answer

So current gain in common emitter configuration equal is beta. So beta equal IC by IB equal IC i

Brian Francisco · Answer

Okay, so we're given the current gain of 75. So that's like current C over current B, that ratio

Given an npn BJT operating in active region, if $V_{BE} = 0.65$ V and $V_{CB} = 8.2$ V, $I_E = 4$ mA and $I_C/I_B = 100$, compute: (a) $I_B$; (b) $I_C$; (c) $V_{CE}$; (d) total power dissipated by the transistor.