Given C=130deg ,B=29deg , and c=15, use the Law of Sines to solve the triangle for the value of a. Given C130B29andc5usethe Law of Sines to solve the triangle for the value of a
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The Law of Sines states that: \[\frac{a}{\sin A} = \frac{c}{\sin C}\] We can rearrange this to solve for \(\sin A\): \[\sin A = \frac{a}{c} \cdot \sin C\] Given \(C=130\deg\) and \(c=15\), we can plug in these values to find \(\sin A\): \[\sin A = \frac{a}{15} Show more…
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