Question

Given char name[80] = ...; char* p = name; To check if the first and the last character in name are equal we use a. \p == (p+strlen(name) - 1); b. name[0] == p[strlen(name)]; c. p == p+strlen(name) - 1; d. p == p[strlen(name) - 1];

          Given
char name[80] = ...;
char* p = name;
To check if the first and the last character in name are equal we use
a. *\*p == *(p+strlen(name) - 1);
b. name[0] == p[strlen(name)];
c. p == p+strlen(name) - 1;
d. *p == p[strlen(name) - 1];

Given
char name[80] = ...;
char* p = name;
To check if the first and the last character in name are equal we use
a. *p == *(p+strlen(name) - 1);
b. name[0] == p[strlen(name)];
c. p == p+strlen(name) - 1;
d. *p == p[strlen(name) - 1];

Added by Jessica L.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Thanks for your feedback!

Given char name[80] = "dots"; char* p = name; To check if the first and the last character in name are equal we use a. strlen(name) Given char name[80], char* p = name; To check if the first and the last character in name are equal we use a. *p = *(p + strlen(name) - 1); b. name[0] == p[strlen(name) - 1]; c. p == p + strlen(name) - 1; d. *p == p[strlen(name) - 1];