Given [ frac{4 x}{x+3}+frac{3}{x-4}=5 ] Choose the possible extraneous roots. Select one or more: a. 0 b. -3 c. 9.22 d. -13.21 e. 4
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Multiply every term by $(x+3)(x-4)$ to clear the fractions: $4x(x-4) + 3(x+3) = 5(x+3)(x-4)$ This simplifies to: $4x^2 - 16x + 3x + 9 = 5x^2 - 20x - 60$ Rearranging terms gives: $x^2 - 7x - 69 = 0$ Factoring the quadratic gives: $(x - 9)(x + 8) = Show more…
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