Given that $\vec{v_1} = \begin{bmatrix} 1 \\ 1 \end{bmatrix}$ and $\vec{v_2} = \begin{bmatrix} -4 \\ -3 \end{bmatrix}$ are eigenvectors of the matrix $A = \begin{bmatrix} 1 & -4 \\ 3 & -6 \end{bmatrix}$ determine the corresponding eigenvalues. $\lambda_1 = $ $\lambda_2 = $
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An eigenvector of a matrix A is a non-zero vector x such that Ax = λx, where λ is a scalar called the eigenvalue corresponding to x. Show more…
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