Given that H$_3$PO$_4$ has three acid-dissociation constants, K$_{a1}$, K$_{a2}$, and K$_{a3}$, what is the expected pH value at the second point of equivalence? ? pK$_{a1}$ ? pK$_{a2}$ ? (pK$_{a2}$+pK$_{a3}$)/2 ? (pK$_{a1}$+pK$_{a2}$)/2 ? pK$_{a3}$ ? (pK$_{a1}$+pK$_{a3}$)/2 ? (pK$_{a1}$+ pK$_{a2}$+pK$_{a3}$)/3
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The solution contains the amphoteric species HPO$_4^{-2}$. Show more…
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At 25 °C, what would the pH at the half-equivalence point be for the first ionization of the triprotic acid phosphoric acid (H3PO4)? (Hint: Look up pKa values on internet and write all three values here before proceeding.) pKa1 - 2.16 pKa2 - 7.21 pKa3 - 12.32
David C.
2. The pKa = pH when the titrant added is ½ the volume needed to get to the equivalence point. Say the equivalence point is at 30.0mL of titrant. The pH at 15.0mL will be equal to the pKa of the acid. With a diprotic acid, the next equivalence point would be at 60.0mL and the pKa2 would be 45.0mL of titrant. Looking at your titration curve for phosphoric acid, determine the equivalence points for the first two protons, then using the logic stated above, determine where the third equivalence point should be on the graph. Look up the pKa3 for phosphoric acid and determine if you can find it on your graph.
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