00:01
In this question, we have been given to find out the values of probability based on the given information.
00:05
So, here in the first part, we can say that we are having the value of mu as 28.
00:10
Now, the value of sigma will be here equals to 7.
00:13
Therefore, the value of probability such that x is here lesser than 48 will be here equals to probability of x minus mu divided by sigma and that will be 48 minus mu which is 28 divided by 7 and this very value will be here probability of z and that is lesser than 2 .86 and it is here going to be 0 .9979 and hence we can say that the value of probability in the second part of this very problem is going to be.
00:45
So, it will be probability of 48 lesser than x and that is lesser than 55 and it is here equals to we can say probability of let us write it will be 2 .857 and then here it is lesser than z and that is lesser than 3 .8 and then here it is 57.
01:04
So, this very value is here going to come around let us write probability of z and that is lesser than 3 .857 and then it will be here minus probability of z lesser than 2 .857.
01:17
So, this very value can be here written as 0...