Given the amplitude spectrum what the power spectrum for the...

Transcript

00:01 Here the solution for the problem.

00:03 Here the solution for the problem will be like this given, given x of n, it will be equal to 2 .2 .2 .2 .0.

00:21 This is like here the total number is 4.

00:23 N is equal to 4.

00:32 X of n e2 power minus j 2 pi divide by n into its capital n into n k and here this will be like here n is equal to 0 to 3 and here x of n e2 power minus j pi by 2 n k and here for this x of 0 will be actually like it will be actually like x of 0 will be actually like here x of 0 here it's taking this as a capital of x of 0 here like x of 0 plus x of 1 plus x of 2 plus x of 3 that will like 2 plus 2 plus 2 is 0 which is like 6 here the value for x of 1 here the value for x of 1 will be like this we will like here summation of n is equal to 0 to 3 x of n e 2 0 minus j pi by 2 and here it will be n minus 1 and yeah we can write this actually and we can write this actually this will be like here x of 0 plus x of 1 e2 power minus j y2 plus x plus x by x of 2 e2 power minus j pi plus x of 3 e2 power minus j 3 pi by 2 and here this value like here 2 plus 2 of minus j and here plus 2 of minus 1 is equal to here it's a plus 0 minus 0 that like 2 minus 2 j of minus 2 will be like minus 2 j and here x of 2 will be here the x of 2 will be x of 2 will be like summation of n is equal to 0 to 3 x of n e2 power minus j pi by 2 and here like n minus 2 and here this value will be actually here it value like x of 0 plus x x x of 1 e2 power minus j pi plus x of 2 and here e 2 power minus j 2 pi plus x of 3 e 2 power minus j 3 pi and here this value like 2 2 minus 1 plus 2 of 1 it's n plus 2 that value will be like here is 2 and here x of 3 will be and here the value of 3 will be and here the value of will be equal to summation of n is equal to 0 to 3 x of n in e2 power minus j pi by 2 and here it will like n into 3 and here that value like x of 0 plus x of 1 e2 power minus j 3 pi by 2 plus x of 2 e2 power minus j 3 pi and here plus x of 3 e 2 power minus j 3 pi by 2 and here this value like 2 plus 2 j and here plus 2 minus 1 that value will be 2 j and now for this and now for this like x of k will be now the x of k will be what do we get the value 6 minus 2j 2 .2 .j.

04:39 This values we get.

04:41 Now what we will do? now what we will do? like angle of xk will be like this.

04:48 Like here, it's a 0 degree...