00:01
In the given question we are told to find the area of a figure.
00:06
So in this figure we can see that there is a semicircle and also there is a right angled triangle.
00:15
So it is right angled over here.
00:18
The center of the semicircle is about here.
00:22
We are told that the hypotenuse of this triangle, this triangular face, is.
00:31
16 .9 feet and the base of this triangle is 11 .9 feet and what we are told to find is we have to find the area of this figure right so first what we could do over here is we can find the length of this side right so if we find the length of this side we can find the length of this side we can divide it by two and find the radius of this semicircle and that would give us the help us find the area of this part of the figure.
01:09
So first it is we have to find one side of this right angled triangle.
01:16
So to find this we can use a theorem called the pythagoras theorem.
01:21
The pythagoras theorem and in this theorem we are told that if we have a triangle with a pythagoras theorem, right angle over here, the length of sides as a, b, and c, where c is the length of the hypotenuse, according to pythagoras theorem, a squared plus b squared is equal to c squared.
01:45
So this is the theorem that we are going to use to find the third side of this triangle, that is we can take a to be the unknown value of this triangle, and we can take a to be the unknown value can take b to be the base of this triangle with 11 .9 feet and c as the hypotenuse which is 16 .9 feet.
02:11
So from the pythagoras theorem we can write a square is then equal to c square minus b square.
02:18
Right...