Question

(5) Max = ??? (Put the integer in the blank below.) (6) Valid interval without outliers: (Put "[a, b]" for the interval below.) (7) Which data will be counted as outliers. (If there's no outlier, put "none", if there's more than one outliers, put them all with comma.)

          (5) Max = ???
(Put the integer in the blank below.)
(6) Valid interval without outliers:
(Put "[a, b]" for the interval below.)
(7) Which data will be counted as outliers.
(If there's no outlier, put "none", if there's more than one outliers, put them all with
comma.)

(5) Max = ???
(Put the integer in the blank below.)
(6) Valid interval without outliers:
(Put "[a, b]" for the interval below.)
(7) Which data will be counted as outliers.
(If there's no outlier, put "none", if there's more than one outliers, put them all with
comma.)

Added by John T.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Kari Hasz

11/30/2022

Step 1

Step 1: Arrange the data in ascending order: 10, 37, 42, 42, 46, 51, 51, 52, 58, 102 Show more…

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Given the data below, find the five-point summary and valid interval for outliers. 42, 37, 51, 51, 58, 102, 52, 46, 42, 10 (1) Min = ??? (Put integer in the blank below) sqrt{10} = 3.2 (2) The first-quartile Q1 = ??? (Put the integer in the blank below.) A = 37 (3) The median M = ??? (Keep 1 decimal in the blank below:) sqrt{44.5} = 6.7 (4) The third-quartile Q3 = ??? (Put the integer in the blank below.) 51 (5) Max = ??? (Put the integer in the blank below) 102 (6) Valid interval without outliers: (Put "(a, b]" for the interval below) (28.5, 64.5] (7) Which data will be counted as outliers. (If there's no outlier, put "none", if there's more than one outliers, put them all with comma.) 10, 102