Given the equation: 3CuSO4 + 2Al >>> 3Cu + Al2(SO4)3 What mass of copper is produced when 40.0g of copper(II) sulfate is mixed with 10.0g of aluminum?
Added by Angela M.
Step 1
0g / 159.61g/mol = 0.2506 mol Moles of Al = mass / molar mass = 10.0g / 26.98g/mol = 0.3705 mol Show more…
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