Question

Given the equation for the reaction, CO2 (g) + 4H2(g) → CH4(g) + 2H2O(g), and the following standard enthalpies of formation: ΔHf CO2(g): 390.3 kJ mol-1 ΔHf CH4(g): -70.9 kJ mol-1 ΔHf H2O(g): -236.3 kJ mol-1 ΔHf H2O(l): -282.5 kJ mol-1 What is the standard enthalpy of reaction in kJ for the reaction shown? Provide the answer in kJ and with the correct significant figures.

Name: given the equation for the reaction co2 g 4h2g ch4g2h2og and the following standard enthalpies of formation changeinhf co2g 3903 kj mol 1 ch4 g 709 kjmol 1h2og 2363 kj mol 1h2ol 2825 kj mol 94242
Uploaded: 2022-05-22T12:26:19-08:00
Duration: 2 min 14 s
Channel: Sri K
Description: given the equation for the reaction co2 g 4h2g ch4g2h2og and the following standard enthalpies of formation changeinhf co2g 3903 kj mol 1 ch4 g 709 kjmol 1h2og 2363 kj mol 1h2ol 2825 kj mol 94242

          Given the equation for the reaction, CO2 (g) + 4H2(g) → CH4(g) + 2H2O(g), and the following standard enthalpies of formation:
ΔHf CO2(g): 390.3 kJ mol-1
ΔHf CH4(g): -70.9 kJ mol-1
ΔHf H2O(g): -236.3 kJ mol-1
ΔHf H2O(l): -282.5 kJ mol-1

What is the standard enthalpy of reaction in kJ for the reaction shown? Provide the answer in kJ and with the correct significant figures.

Added by Patrick C.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Sri K

05/22/2022

Step 1

The standard enthalpy of reaction (ΔHrxn) is given by the sum of the standard enthalpies of formation of the products minus the sum of the standard enthalpies of formation of the reactants. ΔHrxn = ΣΔHf(products) - ΣΔHf(reactants) In this case, the reactants Show more…

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Given the equation for the reaction, CO2 (g) + 4H2(g) → CH4(g) + 2H2O(g), and the following standard enthalpies of formation: ΔHf CO2(g): 390.3 kJ mol-1 ΔHf CH4(g): -70.9 kJ mol-1 ΔHf H2O(g): -236.3 kJ mol-1 ΔHf H2O(l): -282.5 kJ mol-1 What is the standard enthalpy of reaction in kJ for the reaction shown? Provide the answer in kJ and with the correct significant figures.