Given the following balanced equation 2al 6hcl 2alcl3 3h2 if...

Given the following balanced equation: 2Al + 6HCl → 2AlCl3 + 3H2 If you react 55.0 g of Al with excess HCl, what mass of AlCl3 and H2 would be formed? In the above reaction, if you don't wish to use excess HCl, calculate how many moles of HCl you should use to exactly react all of the aluminum. Again, in the above reaction, if you would like to obtain 545 g of AlCl3 as a product, how many grams of aluminum will you need?

Transcript

00:01 Reaction between aluminum and hydrochloric acid which produces aluminum chloride and hydrogen.

00:05 In the first c block of equations we have to calculate mass of hydrogen, mass of aluminum chloride produced upon the reaction and number of most of hcl reacted.

00:15 So let's label this block of blocks of questions as a and the next one is b.

00:22 So first of all, let's calculate number of most of hcl, which is needed.

00:26 According to the equation this number equals to three number of moles of aluminum because of the ratio between these coefficients and then it equals to three times mass of aluminum which is 55 .0 grams divided by the molar mass of aluminum which is 27 .0 grams per mole.

00:51 Now we can calculate this number.

01:01 It equals to 6 .11 mole.

01:06 Okay this part is this small part is done now let's move on let's calculate the mass of hydrogen mass of hydrogen equals to the number of most of hydrogen times its smaller mass and according to this reaction stickometry molar mass of number of most of hydrogen is 1 .5 times larger the number of most of aluminum which is equal which equals to 3 over 2 times 55 0 .0 over 27 times 2 and overall it will be in grams.

01:51 So let's calculate this number.

02:01 It equals to 6 .11 grams.

02:09 Okay now we have to calculate mass of aluminum chloride which equals to the molar mass of aluminum chloride times its number of moles.

02:22 Again let's look at the reaction to geometry.

02:25 Number of moles of aluminum chloride equals to the number of most of aluminum.

02:29 Therefore, you can rewrite it as following...

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