Question

Given the following chemical reaction and standard thermodynamic quantities in the table, FeO(s) + Fe(s) + O2(g) ? Fe2O3(s) FeO(s) Fe(s) O2(g) Fe2O3(s) ?H° (kJ/mol) -271.9 0 0 -822.16 ?S° (J/mol·K) 60.75 27.15 205.0 89.96 at 298 K, ?G° for this reaction is [Select] , and the reaction is [Select]

          Given the following chemical reaction and standard thermodynamic quantities in the table,
FeO(s) + Fe(s) + O2(g) ? Fe2O3(s)
FeO(s) Fe(s) O2(g) Fe2O3(s)
?H° (kJ/mol) -271.9 0 0 -822.16
?S° (J/mol·K) 60.75 27.15 205.0 89.96
at 298 K, ?G° for this reaction is [Select] , and the reaction is
[Select]

Given the following chemical reaction and standard thermodynamic quantities in the table,
FeO(s) + Fe(s) + O2(g) ? Fe2O3(s)
FeO(s) Fe(s) O2(g) Fe2O3(s)
?H° (kJ/mol) -271.9 0 0 -822.16
?S° (J/mol·K) 60.75 27.15 205.0 89.96
at 298 K, ?G° for this reaction is [Select] , and the reaction is
[Select]

Added by Michael R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Vaidik Stats

Step 1

For the reaction FeO(s) + Fe(s) → Fe3O4(s), we have: ΔH° = 271.9 kJ/mol ΔS° = 60.75 J/molK Plugging these values into the equation, we get: ΔG° = 271.9 kJ/mol - (298 K)(0.06075 kJ/molK) = 271.9 kJ/mol - 18.03 kJ/mol = 253.87 kJ/mol Show more…

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Given the following chemical reaction and standard thermodynamic quantities in the table: FeO(s) + Fe(s) â†’ Fe3O4(s) FeO(s) Î”HÂ° (kJ/mol) = 271.9 Î”SÂ° (J/molK) = 60.75 Fe(s) Î”HÂ° (kJ/mol) = 0 Î”SÂ° (J/molK) = 27.15 O2(g) + 2FeO(s) â†’ Fe3O4(s) Î”HÂ° (kJ/mol) = 822.16 Î”SÂ° (J/molK) = 205.0 Î”GÂ° (kJ/mol) = 9668 The Î”GÂ° for this reaction at 298K is [Select] and the reaction is [Select]