Question

t1 ? a t a P S ?11 -t2 a/2a/2 ? a y t? 1 5 ns S Z 

          t1
?
a
t
a
P
S
?11
-t2
a/2a/2
?
a
y
t?
1
5
ns
S
Z
t1 ? a t a P S ?11 -t2 a/2a/2 ? a y t? 1 5 ns S Z

Added by William B.

Close

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
given the following cross section:Determinea) The coordinate đťś‚đť‘  of the centroid S considering t1 = t2 = t; t << ab) The area moment of inertia Iz considering t1 = t; t2 = 2t; t<<a. Hint: In this case, đťś‚đť‘  = a.[answers: a) đťś‚đť‘ =0.9*a; b) Iz = 4/3*t*(a^3)] in n ns P S: a/2 : a/2 n y
Close icon
Play audio
Feedback
Powered by NumerAI
Kathleen Carty Jennifer Stoner
David Collins verified

Khoobchandra Agrawal and 55 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs
*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.
*

Recommended Videos

-
determine-the-moments-of-inertia-i_u-i_v-and-the-product-of-inertia-i_u-v-for-the-rectangular-area-t

Determine the moments of inertia $I_{u}, I_{v}$ and the product of inertia $I_{u v}$ for the rectangular area. The $u$ and $v$ axes pass through the centroid $C$.

Engineering Mechanics: Statics and Dynamics

determine-the-moment-of-inertia-of-the-composite-area-about-the-y-axis-ty-also-find-the-x-distance-t0-the-centroid-from-the-y-axis-then_-find-the-moment-of-inertia-about-the-y-axis-passing-t-80402

Determine the moment of inertia of the composite area about the y-axis (Iy). Also, find the x distance to the centroid from the y-axis (x̄). Then, find the moment of inertia about the y-axis passing through the centroid (Īyʔ).

Hafiz S.
i0-su-locate-the-centroid-y-of-the-cross-section-and-determine-the-moment-of-inertia-of-the-section-about-the-axis-005-03-m-02-m-02-m-02-m-02-m-prob-10-50-40752

Locate the centroid y of the cross section and determine the moment of inertia of the section about the x' axis.

Sri K.
*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,398 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,591 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,938 solutions
*

Transcript

-
00:01 Hello friends here we have to calculate moment of inertia i u i v and product of inertia uv for rectangular area shown in the figure let us start solving it since rectangular area is symmetrical to x and y axis hence i x y x y is zero moment of inertia about x x x x x axis is 112 of 120 into 30 cube that is 0 .27 into 10 to the power 6 millimeter to the power 4 and iy2v 112 of 30 into 120 cube is called to 4 .32 into 10 to the power 6 millimeter to the power 4 .4.
01:44 Moment of inertia about the axis u can be defined as ix plus i y upon 2 plus i x minus i y upon 2 cos of 2 theta minus i x by sine of 2 theta putting the values i x is 027 10 to the power 6 i y is 4 .3 2 10 to the over 6 divided by 2 plus 0 .27 10 to the power 6 minus 4 .32 into 10 to the power 6 upon 2 cost of 2 into 30 plus sorry minus i x by 0 so this term becomes 0 so on solving it you will get moment of inertia about ux is having the value 1 .28 into 10 to the power 6 millimeter to the power 4 about axis v can be written as ix plus iy 52 minus i x minus i y y by 2 cos of 2 theta plus i x by sine of 2 theta putting the values 07 10 to the power 6 plus 4 .32 into 10 to the power 6 divided by 2 minus 0 .27 10 to the power 6 minus 4 .3 to 10 to the power 6 upon 2 theta is given 30 degrees so it becomes 60 and this term is 0 so you will get moment of inertia along v x to v 3 .31 into 10 to the power 6 millimeter to the power 4...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever