Question

Given the following data, calculate △Hf°per mol CaCl2(s): enthalpy of dissociation of 0.5 mol Cl2(g), 122 kJ; electron affinity of 1 mol Cl(g): -349 kJ mol-1; enthalpy of sublimation of Ca(s), +178.2 kJ mol-1; first ionization energy of Ca(g), +590kJ mol-1; second ionization energy of Ca(g), +1145 kJ mol-1; lattice energy of CaCl2(s), 2223 kJ mol-1.

Name: given the following data calculate hfper mol cacl2s enthalpy of dissociation of 05 mol cl2g 122 kj electron affinity of 1 mol clg 349 kj mol 1 enthalpy of sublimation of cas 1782 kj mol 1 first ioniza
Uploaded: 2022-12-28T16:46:51-08:00
Duration: 3 min 4 s
Channel: David Collins
Description: given the following data calculate hfper mol cacl2s enthalpy of dissociation of 05 mol cl2g 122 kj electron affinity of 1 mol clg 349 kj mol 1 enthalpy of sublimation of cas 1782 kj mol 1 first ioniza

          Given the following data, calculate △Hf°per mol CaCl2(s): enthalpy of dissociation of 0.5 mol Cl2(g), 122 kJ; electron affinity of 1 mol Cl(g): -349 kJ mol-1; enthalpy of sublimation of Ca(s), +178.2 kJ mol-1; first ionization energy of Ca(g), +590kJ mol-1; second ionization energy of Ca(g), +1145 kJ mol-1; lattice energy of CaCl2(s), 2223 kJ mol-1.

Added by Gene N.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert David Collins

12/28/2022

Step 1

Given that the enthalpy of dissociation of 0.5 mol Cl2(g) is 122 kJ, the dissociation of 1 mol of Cl2(g) to 2 mol of Cl(g) would be: \[ \Delta H_{\text{dissociation}} = 2 \times 122 \text{ kJ} = 244 \text{ kJ} \] Show more…

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Given the following data, calculate △Hf°per mol CaCl2(s): enthalpy of dissociation of 0.5 mol Cl2(g), 122 kJ; electron affinity of 1 mol Cl(g): -349 kJ mol-1; enthalpy of sublimation of Ca(s), +178.2 kJ mol-1; first ionization energy of Ca(g), +590kJ mol-1; second ionization energy of Ca(g), +1145 kJ mol-1; lattice energy of CaCl2(s), 2223 kJ mol-1.