Given the following enthalpy change values for the reactions below:
A + B → 2C ; ΔrH = 170.5 kJ mol^-1
E + F → C + 2D ; ΔrH = -268.5 kJ mol^-1
1/2 E + G → H ; ΔrH = 496.6 kJ mol^-1
Calculate ΔrH for the following reaction (in kJ mol^-1) using Hess's Law:
A + B + 4G + 4D → 4H + 2F