00:01
Hi, in this question we are given with combustion reaction of propane.
00:04
1 mole of propane react with 5 moles of oxygen gas to produce 3 moles of carbon dioxide and 4 moles of water vapor.
00:11
Here, delta h0 combustion value for this reaction is 2044 kilojoules.
00:16
We are asked to calculate the mass of propane that must be combusted to provide enough thermal energy to heat, water that has mass 946 .4 grams.
00:30
Initial temperature of water was 21 degrees celsius and final temperature is 100 degrees celsius.
00:36
Specific heat of water is 4 .184 jule per gram per kelvin.
00:41
Here we can say that heat gain by water will be equal to m cp, delta t.
00:52
M is the mass of water, cp is the specific heat and delta t's change in temperature.
00:56
We can substitute the given values here.
00:58
In this manner, now we can eliminate the common units gram will be cancelled from gram.
01:04
Kelvin will be cancelled from kelvin...