Given the following two half equations and figure to the right, answer questions 32 - 36 for this galvanic cell: Sn²?(aq) + 2e? ? Sn(s) ?° = -0.136 V Ag?(aq) + e? ? Ag(s) ?° = +0.799 V 32. What is the half equation occurring at the anode (left cell)? a. Ag?(aq) + e? ? Ag(s) b. Sn²?(aq) + 2e? ? Sn(s) c. Ag(s) ? Ag?(aq) + e? d. Ag?(aq) + Sn²?(aq) ? Ag(s) + Sn(s) e. Sn(s) ? Sn²?(aq) + 2e?
Added by Mandy Y.
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The half equation occurring at the anode (left cell) is the oxidation half-reaction. In this case, it is the reaction where Sn(s) is oxidized to Sn2+(aq) and releases 2 electrons. So, the correct answer is E. Sn(s) --> Sn2+(aq) + 2e-. Show more…
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