Given the function $f(t) = t(t+3)(t-1)$ its $f$-intercept is its $t$-intercepts are Enter a point [more..]
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The given function is $f(t) = t(t+3)(t-1)$. Substitute $t=0$ into the function: $f(0) = 0(0+3)(0-1)$ $f(0) = 0(3)(-1)$ $f(0) = 0$ So, the $f$-intercept is 0. This can be written as a point $(0, 0)$. Show more…
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