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Given the function $p(x) = \begin{cases} -3x - 4 & x < -5 \ -4x^2 - 8x + 3 & -5 \le x < 3 \ 2x + 1 & x \ge 3 \end{cases}$ \newline Calculate the following values: \newline $p(6) = $ \newline $p(-9) = $ \newline $p(-5) = $

          Given the function $p(x) = \begin{cases} -3x - 4 & x < -5 \ -4x^2 - 8x + 3 & -5 \le x < 3 \ 2x + 1 & x \ge 3 \end{cases}$ \newline Calculate the following values: \newline $p(6) = $ \newline $p(-9) = $ \newline $p(-5) = $
        
Given the function p(x) =  -3x - 4     x < -5  -4x^2 - 8x + 3     -5 ≤ x < 3  2x + 1     x ≥ 3 Calculate the following values: p(6) = p(-9) = p(-5) =

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Given the function p(x)={(-3x-4,x<-5),(-4x^(2)-8x+3,-5<=x<3),(2x+1,x>=3):} Calculate the following values: p(6)= p(-9)= p(-5)= -3x-4 x<-5 Given the function p( 4x2- 8x+3 5<<3 2x+1 Calculate the following values x>3 p(6= =6-d p-5=
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Transcript

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00:01 Okay, you can see from looking at this question that we can further factor this completely.
00:05 So it's right, this is x plus 3 times 2x minus 1 times 2x plus 1.
00:14 We know that we can set each factor equal to 0 and solve the equation for x...
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