00:01
In this problem, we're given the following information and asked to find the equilibrium constant.
00:05
Our first order of business will be to find our change of heat for our reaction.
00:15
That will be equal to, let me jot this down, 2 times so3 is negative 395.
00:26
We'll subtract from that 2 times negative 297.
00:29
To this we will add 1 times 0.
00:38
Let me see, do i have this figured out anywhere? i doubt it.
00:43
Nope.
00:44
Let's do this.
00:45
2 times negative 395 minus parentheses 2 times negative 27 is negative 196.
01:12
Then our entropy change will be equal to 2 times so3 is 256.
01:26
We'll subtract from that 2 times 249 and 1 times 205.
01:39
2 times 256.
01:45
We'll subtract from that parentheses 2, or parentheses, parentheses, 2 times 249 plus 205.
02:00
And this will equal, i don't feel like that's right.
02:19
I'm going to try this one again.
02:24
Oh, it isn't right.
02:30
256 times 2.
02:32
That's 512.
02:34
2 times 249.
02:39
It is negative 191 kilojoules.
02:51
So now our last step, the ln of our equilibrium constant will be equal to our delta g over rt.
03:05
This will be equal to negative 191, and actually it's a negative of that.
03:12
So it's a negative of this times 0 .008314 kilojoules per mole k times 298.
03:32
Let me do this.
03:36
Negative 191...