Graph the feasible region for the follow system of inequalities by drawing a polygon around the feasible region. Click to set the corner points. $$ \begin{cases} x+y \le 11 \\ -x+y \ge 1 \\ x \ge 2 \end{cases} $$
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1. $x+y \le 11$ can be rewritten as $y \le -x + 11$. The boundary line is $y = -x + 11$. 2. $-x+y \ge 1$ can be rewritten as $y \ge x + 1$. The boundary line is $y = x + 1$. 3. $x \ge 2$ is a vertical line at $x = 2$. Show more…
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