00:01
This question wants me to graph a couple of quadratics.
00:06
So we're going to have the first one, f of x, is going to equal x squared plus 2.
00:14
So the first thing i'm going to do is i'm going to find my axis symmetry.
00:23
So there'll be negative b over 2 times a.
00:29
So there is no b.
00:30
So my axis symmetry is at zero.
00:33
So i'm going to plug zero in to find my vertex symmetry.
00:39
So 0 squared is 0 plus 2 is 2.
00:43
So 02 would be my vertex.
00:51
And now i'm going to plug in value.
00:52
So if i plug it 1, 1 squared is 1 plus 2 is 3.
00:56
So 1 and 3 and it's reflection.
00:59
Let's plug in 2 now.
01:01
2 squared is 4 plus 2 is 6.
01:04
So 2 and 6 and it's reflection.
01:12
And the rest would be off the graph.
01:13
So the first one is going to look like this.
01:20
There are no x intercepts for this one.
01:23
My y intercept for this would be 0 .2.
01:30
My domain is from negative infinity to infinity.
01:34
That's always going to be the case for quadratics.
01:37
My range, though, the lowest i go is 2, and the highest i go is infinity.
01:46
And then increasing interval, well, it starts to increase.
01:50
I'm looking at my x value.
01:51
So it's from 0 to infinity.
01:53
And it's decreasing from negative infinity to zero.
01:59
And i'm going to have a relative min at 0, 2, because that is my lowest, my lowest value.
02:11
So let's do the next one.
02:13
The next one is f of x equals x squared minus 2x minus 8.
02:21
So again, i'm going to find my axis symmetry.
02:25
So it's going to be negative b, so positive 2 over 2 times 1.
02:30
Which is 1.
02:31
So my axis symmetry is going to be at 1.
02:34
So to find my vertex, i'm going to plug in 1.
02:37
So i'm going to get 1 squared, which is 1, minus 2 times 1, which is 2, minus 8.
02:44
So i get negative 3 minus 8, negative 11.
02:51
Let's go back on that's not right.
02:55
So it's going to be negative 1 here.
02:59
So negative 1 minus negative 9.
03:01
There we go...