Question

Graph the given system of inequalities.\\ $\begin{cases} 2x + y \ge -8\\ 4x + 2y \le 0 \end{cases}$\\ Use the graphing tool to graph the system.

          Graph the given system of inequalities.\\
$\begin{cases} 2x + y \ge -8\\ 4x + 2y \le 0 \end{cases}$\\
Use the graphing tool to graph the system.
        
Graph the given system of inequalities.

2x + y ≥ -8
 4x + 2y ≤ 0

Use the graphing tool to graph the system.

Added by Yolanda B.

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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Graph the given system of inequalities. 2x+y>=-8 4x+2y<=0 Use the graphing tool to graph the system. Graph the given system of inequalities 2x+y-8 4x+2y0 Use the graphing tool to graph the system Click to enlarge graph
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Transcript

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00:01 In this problem, we're being asked to graph the system of inequalities.
00:04 Well, let's first start with our, let's begin with the first inequality.
00:07 X squared plus y squared is less than equal to nine.
00:10 Remember, this is the equation for a circle whose center is at the origin.
00:15 And we know it's centered at the origin because it's just x squared and y squared.
00:18 Now remember, the radius will be the square root of our constant at the end.
00:22 Well, the square of the nine is equal to three.
00:24 So if we were to draw this circle, we have our center at the origin, and it's radius is at three.
00:29 So we know four points on it.
00:30 It'd be three units to the right, three units up, three units to the left, and three units down.
00:36 So now that we have these points, we can go ahead and draw our circle.
00:41 Okay, so now let's look at our second inequality.
00:44 Why is less than equal to four minus one half x squared? well, notice we have a quadratic, so we know the shape is going to be a parabola.
00:52 In this case, for transformations, it went up four units.
00:57 Okay, so now that we know it just went up four units, we're going to have a vertical string, a string, and because a is less than zero, we know that it's going to open downwards.
01:06 So we can find a couple of our points by substituting values for x into our function.
01:11 So first off, let's try when x is equal to 1.
01:13 So we would have y equal to 4 minus 1 1⁄2 times 1 squared.
01:18 Well, 1 squared is just 1...
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