00:01
Hi there.
00:02
To solve this problem, we need to look at the relationship between wavelength and frequency.
00:07
It is known that the wavelength, lambda, times the frequency new, when multiplied together, equal the speed of light.
00:17
So we can use this equation to solve for the wavelength.
00:21
Speed of light, we are given the question as 3 .0 times 10 to the 8 meters per second.
00:33
And wavelength we're trying to find.
00:37
Frequency we are given as 6 .05 times 10 to the 14th hertz and hertz means per second.
00:52
Okay, so to isolate wavelength by itself, we need to divide both sides by 6 .05 times 10 to the 14.
01:10
When we do that, oops, when we do that, we see that the entire 6 .05 times 10 to the 14th cancels on the right side and the unit per second cancels on the left side.
01:27
So grabbing our calculators and dividing 3 .0 times 10 to the 8th by 6 .05 times 10 to the 14th.
01:34
I get 4 .958.
01:37
So i am rounding that to three significant digits, which would be 4 .96 times 10 to the negative 7.
01:47
And remember, these are meters because meters have meters...