00:01
It is given that the number of treatments that we need to compare is 3.
00:05
So we can update this with 3 and it is also said that there are 6 components in each of these 3 treatments.
00:14
So 6 into 3 there will be 18 components in total.
00:17
Now we can set up the null hypothesis as the usually we take that the 3 treatments or the means are the same for the groups given.
00:28
So here 3 groups are given.
00:30
Against the alternate hypothesis for the anova is that at least one mean is different from others.
00:46
This is the alternate hypothesis of our interest.
00:54
Now we can complete the anova table using the given of information.
01:01
So usually anova table the headings are the source, sum of squares, degrees of freedom and mean sum of squares, then f calculated and f critical.
01:17
Or here we can include instead of f critical we can include the p value corresponding to this calculated value.
01:27
Here the sources are given as treatments and treatments error and total.
01:37
The sum of squares are filled with the this is the given information 1184.
01:43
Here it is 1000 and this is 2184.
01:47
Now we have to fill the others here.
01:49
Here the degrees of freedom will be usually k minus 1 that is 3 is the number of groups here.
01:56
So k minus 1 2 and here the degrees of freedom is n minus 1.
02:01
That means we know that there are 18 components minus 1 so that here it is 17 and for the error degrees of freedom means 17 minus 2 that is the degrees of freedom between total and treatments...