h. If we increase the side length of the square from 1.9 cm to 4.4 cm, the square's perimeter increases from 7.6 cm to 17.6 cm.
i. Determine the value of ΔP as s increases from 1.9 cm to 4.4 cm.
ΔP = 10
j. As the values s and P vary together in the relationship where P = 4s, define ΔP in terms of Δs.
ΔP = 4Δs
k. Which of the following describes a relationship defined by the formula P = 4s? (Select all that apply.)
Since s and P are proportional, P varies at a constant rate of change with respect to s.
For any change in s, Δs, away from a point (s₁, P₁) in the relationship, ΔP = 4Δs.
Given any point (s, P) in the relationship, P is always 4 times as large as s.
Given any two points in the relationship (s₁, P₁) and (s₂, P₂), (P₂ - P₁) / (s₂ - s₁) = 4.
The point (4.4, 17.6) in the relationship conveys that 17.6 = 4(4.4).