Question

H12D 2. Find the value of cach expression by subatituting \( x=\frac{1}{2} \) and \( y=-\frac{1}{3} \). (1) \( x+y= \) (2) \( y-x= \) (3) \( 2 x+3 y= \) (4) \( 4 x-9 y+5= \) (5) \( 2 x+\frac{3}{2} y= \) (6) \( \frac{1}{3} x+\frac{5}{2} y= \) (7) \( \frac{5}{3} x-\frac{1}{5} y= \) (8) \( \frac{2 x+15 y}{6}= \)

          H12D
2. Find the value of cach expression by subatituting \( x=\frac{1}{2} \) and \( y=-\frac{1}{3} \).
(1) \( x+y= \)
(2) \( y-x= \)
(3) \( 2 x+3 y= \)
(4) \( 4 x-9 y+5= \)
(5) \( 2 x+\frac{3}{2} y= \)
(6) \( \frac{1}{3} x+\frac{5}{2} y= \)
(7) \( \frac{5}{3} x-\frac{1}{5} y= \)
(8) \( \frac{2 x+15 y}{6}= \)

H12D
2. Find the value of cach expression by subatituting x=(1)/(2) and y=-(1)/(3).
(1) x+y=
(2) y-x=
(3) 2 x+3 y=
(4) 4 x-9 y+5=
(5) 2 x+(3)/(2) y=
(6) (1)/(3) x+(5)/(2) y=
(7) (5)/(3) x-(1)/(5) y=
(8) (2 x+15 y)/(6)=

Added by Aaron M.

Beginning and Intermediate Algebra

Sherri Messersmith 3rd Edition

Chapter 5

Instant Answer

Solved by Expert Leslie Deeb

Step 1

Step 1: Substitute \( x = \frac{1}{2} \) and \( y = -\frac{1}{3} \) into each expression. Show more…

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H12D 2. Find the value of cach expression by subatituting \( x=\frac{1}{2} \) and \( y=-\frac{1}{3} \). (1) \( x+y= \) (2) \( y-x= \) (3) \( 2 x+3 y= \) (4) \( 4 x-9 y+5= \) (5) \( 2 x+\frac{3}{2} y= \) (6) \( \frac{1}{3} x+\frac{5}{2} y= \) (7) \( \frac{5}{3} x-\frac{1}{5} y= \) (8) \( \frac{2 x+15 y}{6}= \)