H2(g) + Cl2(g) --> HCl(g) Consider the unbalanced equation above. 2.25L of H2 and 4.95L of Cl2 are reacted under the same conditions of temperature and pressure. How many liters of HCl will be produced?
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Step 1
Given: Volume of H2 = 2.25 L Volume of Cl2 = 4.95 L Moles of H2 = 2.25 L / 22.4 L/mol = 0.1 mol Moles of Cl2 = 4.95 L / 22.4 L/mol = 0.22 mol Show more…
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