00:01
Here in this given problem at the given instant height of the plane, aeroplane above the ground that is given to be 60 meter, speed of the plane v 0 at that instant that is 45 meter per second.
00:37
So, when the weight is dropped from the aeroplane, it will be following a parabolic path and will hit the target over here at the ground.
00:51
So, we have to find the distance of the point from the target at which we should drop the so that weight may hit the target exactly and that is in the first part of the problem.
01:12
So, using vertical motion first of all and applying second equation of motion in it.
01:19
So, we can say using second equation of motion in vertical motion of the weight dropped h is equal to v o y initial vertical velocity which is 0 into t plus half g t square.
01:53
Using that we will get we will find time taken by the weight to come to the ground.
01:59
So, for h this is 60 is equal to 0 plus half times 9 .8 and square of time which is missing...