Hayden is initially at rest. After jumping from the high ground, Hayden has a horizontal velocity when he collides with the vampire guy who was at rest. They travel off together. What would their final velocity be
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4. Consider two balls in motion at the same time. Joe drops the first ball from rest at height h. Directly below Joe, on the ground, Hayley simultaneously tosses a second ball upward with speed v0. a. If the two balls collide at the moment the second ball is instantaneously at rest, what is the height of the collision? b. What is the relative speed of the balls when they collide?
Madhur L.
Due to ejection of mass from a moving system (which moves due to inertia) in a direction perpendicular to it, the velocity of moving system does not change. The momentum change being adjusted by the forces on the rails. Hence in our problem velocities of buggies change only due to the entrance of the man coming from the other buggy. From the Solving (1) and (2), we get $$ v_{1}=\frac{m v}{M-m} \text { and } v_{2}=\frac{M v}{M-m} $$ As $$ \begin{gathered} \vec{v}_{1} \uparrow \downarrow \vec{v} \text { and } \overrightarrow{v_{2}} \uparrow \uparrow \vec{v} \\ \vec{v}_{1}=\frac{-m \vec{v}}{(M-m)} \text { and } \overrightarrow{v_{2}}=\frac{M \vec{v}}{(M-m)} \end{gathered} $$ So,
Physical Fundamentals Of Mdchanics
Laws of Conservation of Energy, Momemtum, and Angular Momentum
Two acrobats, each of 60.0 kg, launch themselves together from a swing, holding hands. Their velocity at launch was 7.60 m/s and the angle of their initial velocity relative to the horizontal was 53.0 degrees upwards. At the top of their trajectory, their act calls for them to push against each other in such a way that one of them becomes stationary in mid-air and then falls to the safety net while the other speeds away, to reach another swing at the same height at that of the swing they left.
Kritika M.
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