Question

H3CCH=CHCH3 -> H2NCH2CH2CH2CH2CH2CH2NH2 Reagents a. Br2, CH2Cl2 b. KCN, HCN c. LiAlH4 then H3O+ d. H2, Pd/C e. excess NBS, CCl4 f. excess CH3MgBr, ether then H3O+ g. H3O+, heat Select reagents from the table to carry out this transformation. (Enter your answer as a single string of letters representing the reagents in the order that you wish to use them, i.e. bdce.)

          H3CCH=CHCH3 -> H2NCH2CH2CH2CH2CH2CH2NH2

Reagents
a. Br2, CH2Cl2
b. KCN, HCN
c. LiAlH4 then H3O+
d. H2, Pd/C
e. excess NBS, CCl4
f. excess CH3MgBr, ether then H3O+
g. H3O+, heat

Select reagents from the table to carry out this transformation.

(Enter your answer as a single string of letters representing the reagents in the order that you wish to use them, i.e. bdce.)

H3CCH=CHCH3 -> H2NCH2CH2CH2CH2CH2CH2NH2

Reagents
a. Br2, CH2Cl2
b. KCN, HCN
c. LiAlH4 then H3O+
d. H2, Pd/C
e. excess NBS, CCl4
f. excess CH3MgBr, ether then H3O+
g. H3O+, heat

Select reagents from the table to carry out this transformation.

(Enter your answer as a single string of letters representing the reagents in the order that you wish to use them, i.e. bdce.)

Added by Robert S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

05/24/2023

Step 1

First, we need to convert the alkene (C=C) to an alkyl halide. We can use $\textbf{Br}_2$ for this purpose. So, the first reagent is $\textbf{b}$. Show more…

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H3CCH=CHCH3 -> H2NCH2CH2CH2CH2CH2CH2NH2 Reagents a. Br2, CH2Cl2 b. KCN, HCN c. LiAlH4 then H3O+ d. H2, Pd/C e. excess NBS, CCl4 f. excess CH3MgBr, ether then H3O+ g. H3O+, heat