Healthy people have body temperatures that are normally distributed with a mean of 98.20∘F98.20∘F and a standard deviation of 0.62∘F0.62∘F . a) If a healthy person is randomly selected, what is the probability that he or she has a temperature above 98.3∘F98.3∘F? b) What body temperature do only 1% of healthy people exceed? ∘
Added by Anthony C.
Step 1
3∘F, we need to calculate the z-score first: z = (98.3 - 98.2) / 0.62 = 0.1613 Then, we can use a standard normal distribution table or calculator to find the probability: P(z > 0.1613) = 0.4364 Show more…
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