00:01
So here in this question, first we convert the initial temperature to the kelvin and use the ideal gas load to find the initial specific volume.
00:09
So, using ideal gas law, gas law, that is, v1 is equal to rt1 by p1, and that is 287 joules per kilogram kelvin into 300 .15 kelvin.
00:31
By 95 ,000 pascals and that is 0 .906 meter cube per second, sorry, per kilogram.
00:42
Then we calculate the temperature at the end of the compression process using the compression ratio, that is, t2 is equal to t1 into r raised to the power k minus 1, that is 300 .15 into 8 raised to the power 1 .4 minus 1, that is 300 .15 kelvin into 8 risk to the power 0 .4.
01:06
And from here, t2 roughly comes out to be 791 .6 kelvin...