Question

Heat conduction occurs through any material, represented here by a rectangular bar, whether window glass or walrus blubber. The temperature of the material is T2 on the left and T1 on the right, where T2 is greater than T1. The rate of heat transfer by conduction is directly proportional to the surface area A, the temperature difference T2 - T1, and the substance's conductivity k. The rate of heat transfer is inversely proportional to the thickness d. frac{Q}{t} = frac{kA(T_2 - T_1)}{d} where Q / t is the rate of heat transfer in watts, k is the thermal conductivity of the material, A and d are its surface area and thickness, and (T2 - T1) is the temperature difference across the slab. Case 1. A window in a house has a rectangular shape of 2.0 m by 1.0 m. The glass in the window is 0.5 cm thick, with a thermal conductivity of 0.84 W/(m °C). The temperature in the house is 22.0 °C, and the temperature outside is 4 °C. How much heat is lost through this window in one minute? Don't use scientific notations

          Heat conduction occurs through any material, represented here by a rectangular bar, whether window glass or walrus blubber. The temperature of the material is T2 on the left and T1 on the right, where T2 is greater than T1. The rate of heat transfer by conduction is directly proportional to the surface area A, the temperature difference T2 - T1, and the substance's conductivity k. The rate of heat transfer is inversely proportional to the thickness d.
frac{Q}{t} = frac{kA(T_2 - T_1)}{d}
where Q / t is the rate of heat transfer in watts, k is the thermal conductivity of the material, A and d are its surface area and thickness, and (T2 - T1) is the temperature difference across the slab.
Case 1.
A window in a house has a rectangular shape of 2.0 m by 1.0 m. The glass in the window is 0.5 cm thick, with a thermal conductivity of 0.84 W/(m °C). The temperature in the house is 22.0 °C, and the temperature outside is 4 °C. How much heat is lost through this window in one minute? Don't use scientific notations

$Heat conduction occurs through any material, represented here by a rectangular bar, whether window glass or walrus blubber. The temperature of the material is T2 on the left and T1 on the right, where T2 is greater than T1. The rate of heat transfer by conduction is directly proportional to the surface area A, the temperature difference T2 - T1, and the substance's conductivity k. The rate of heat transfer is inversely proportional to the thickness d. fracQt = frackA(T2 - T1)d where Q / t is the rate of heat transfer in watts, k is the thermal conductivity of the material, A and d are its surface area and thickness, and (T2 - T1) is the temperature difference across the slab. Case 1. A window in a house has a rectangular shape of 2.0 m by 1.0 m. The glass in the window is 0.5 cm thick, with a thermal conductivity of 0.84 W/(m °C). The temperature in the house is 22.0 °C, and the temperature outside is 4 °C. How much heat is lost through this window in one minute? Don't use scientific notations$

Added by Santiago W.

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