00:01
So here in this question we are given the value of sink temperature and the sink temperature is represented by ts which will be equal to 7 degrees celsius.
00:09
We are given our source temperature and the source temperature is represented by a to which will be equals to 22 degrees celsius.
00:17
So we can say that in k1, sink temperature will be equal to 280 kelvin in the terms of kelvin and source temperature will be 295 kelvin.
00:30
So, in the first part, we have to find out the efficiency of carnot heat engine.
00:40
So this will be n is equal to 1 minus temperature of sync divided by the temperature of source.
00:48
So, neta will be equals to 1 minus 280 divided by the 295.
00:52
So from here we can say that the value of nita will be equals to 0 .051 or nita will be equals to 5 .1%.
01:00
So this is the answer here to this part.
01:04
Now in the next part we have to find out the coefficient of performance...