Question

SP3. A Carnot engine operating in reverse as a heat pump moves heat from a cold reservoir at 7°C to a warmer one at 22°C. a) What is the efficiency of a Carnot engine operating between these two temperatures? b) If the Carnot heat pump releases 250 J of heat into the higher-temperature reservoir in each cycle, how much work must be provided in each cycle? c) How much heat is removed from the 7°C reservoir in each cycle? d) The performance of a refrigerator or heat pump is described by a ""coefficient of performance"" defined as $K = Q_c/W$. What is the coefficient of performance for our Carnot heat pump?

          SP3. A Carnot engine operating in reverse as a heat pump moves heat from a cold reservoir at 7°C to a warmer one at 22°C.
a) What is the efficiency of a Carnot engine operating between these two temperatures?
b) If the Carnot heat pump releases 250 J of heat into the higher-temperature reservoir in each cycle, how much work must be provided in each cycle?
c) How much heat is removed from the 7°C reservoir in each cycle?
d) The performance of a refrigerator or heat pump is described by a ""coefficient of performance"" defined as $K = Q_c/W$. What is the coefficient of performance for our Carnot heat pump?
        
Show more…
SP3. A Carnot engine operating in reverse as a heat pump moves heat from a cold reservoir at 7°C to a warmer one at 22°C.
a) What is the efficiency of a Carnot engine operating between these two temperatures?
b) If the Carnot heat pump releases 250 J of heat into the higher-temperature reservoir in each cycle, how much work must be provided in each cycle?
c) How much heat is removed from the 7°C reservoir in each cycle?
d) The performance of a refrigerator or heat pump is described by a ""coefficient of performance"" defined as K = Qc/W. What is the coefficient of performance for our Carnot heat pump?

Added by Michelle V.

Close

University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
A Carnot engine operating in reverse as a heat pump moves heat from a cold reservoir at 7°C to a warmer one at 22°C. a) What is the efficiency of a Carnot engine operating between these two temperatures? b) If the Carnot heat pump releases 250 J of heat into the higher-temperature reservoir in each cycle, how much work must be provided in each cycle? c) How much heat is removed from the 7°C reservoir in each cycle? d) The performance of a refrigerator or heat pump is described by a "coefficient of performance" defined as K = Qc/W. What is the coefficient of performance for our Carnot heat pump?
Close icon
Play audio
Feedback
Powered by NumerAI
Danielle Fairburn Ivan Kochetkov
David Collins verified

Sri K and 57 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
a-carnot-engine-is-operated-between-two-heat-reservoirs-at-temperatures-of-510-k-and-305-k-a-if-the-engine-receives-645-kj-of-heat-energy-from-the-reservoir-at-510-k-in-each-cycle-how-many-joules-per-

A Carnot engine is operated between two heat reservoirs at temperatures of 510 K and 305 K. (a) If the engine receives 6.45 kJ of heat energy from the reservoir at 510 K in each cycle, how many joules per cycle does it discard to the reservoir at 305 K? J (b) How much mechanical work is performed by the engine during each cycle? J (c) What is the thermal efficiency of the engine? %

Suman Saurav T.

carnot-cycle-123-we-examine-a-carnot-cycle-engine-next-time-youll-learn-about-the-fridge-version_-hot-reservoir-at-qh-hot-reservoir-at-t-qh-engine-wby-fridge-won-ta-ta-cold-reservoir-at-t-co-74967

Carnot Cycle We examine a Carnot Cycle engine. Next time you'll learn about the fridge version. First consider a Carnot engine that operates between a hot reservoir at 58°C and a cold reservoir at -16°C. In running 25 minutes, this engine absorbs 600 J of heat from the hot reservoir. 1) How much heat does it expel to the cold reservoir? Qc = 2) How much work does it do in this amount of time? Wby = 3) What is the upper limit on the efficiency of any heat engine operating between these two reservoirs? εmax =

Marinus K.

a-heat-engine-operates-in-a-carnot-cycle-between-910c-and-325c-it-absorbs-22200-j-of-energy-per-cycle-from-the-hot-reservoir-the-duration-of-each-cycle-is-550-sa-what-is-the-mechanical-power-54741

A heat engine operates in a Carnot cycle between 91.0°C and 325°C. It absorbs 22,200 J of energy per cycle from the hot reservoir. The duration of each cycle is 5.50 s. (a) What is the mechanical power output of this engine? (b) How much energy does it expel in each cycle by heat? Step 1 (a) The temperatures of the reservoirs used by this engine are Tc, the cold reservoir temperature, and Th, the hot reservoir temperature. We first convert Celsius to absolute temperatures. We find Tc = °C + 273 = K and Th = °C + 273 = K.

Suman K.


*

Recommended Textbooks

-
University Physics with Modern Physics

University Physics with Modern Physics

Hugh D. Young 14th Edition
achievement 1,702 solutions
Physics: Principles with Applications

Physics: Principles with Applications

Douglas C. Giancoli 7th Edition
achievement 1,513 solutions
Fundamentals of Physics

Fundamentals of Physics

David Halliday, Robert Resnick , Jearl Walker 10th Edition
achievement 1,674 solutions

*

Transcript

-
00:01 So here in this question we are given the value of sink temperature and the sink temperature is represented by ts which will be equal to 7 degrees celsius.
00:09 We are given our source temperature and the source temperature is represented by a to which will be equals to 22 degrees celsius.
00:17 So we can say that in k1, sink temperature will be equal to 280 kelvin in the terms of kelvin and source temperature will be 295 kelvin.
00:30 So, in the first part, we have to find out the efficiency of carnot heat engine.
00:40 So this will be n is equal to 1 minus temperature of sync divided by the temperature of source.
00:48 So, neta will be equals to 1 minus 280 divided by the 295.
00:52 So from here we can say that the value of nita will be equals to 0 .051 or nita will be equals to 5 .1%.
01:00 So this is the answer here to this part.
01:04 Now in the next part we have to find out the coefficient of performance...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever