00:01
Hello, here we have to solve the following problem.
00:03
In a factory part can be produced by three machines a, b and c.
00:08
So probability for other following probability being produced by a is 0 .3 or 30 % and actually i'll just leave it as 0 .3.
00:20
B would be also 0 .3 and c is 0 .4.
00:29
And here the probability for a being defective is 1 % so that's to be defective is 0 .01, to be okay or normal is 0 .99.
00:43
B, for b that is basically to be defective is 0 .03, to be normal is 0 .97 and for c to be defective the probability is 0 .02, to be normal is 0 .98.
01:00
All right and here we have to calculate probability that the broken part of the defective is produced by c.
01:13
So first let's calculate probability for the part to be defective that is 0 .3 times 0 .01 plus 0 .3 times 0 .03 plus 0 .4 times 0 .02 that is 0 .02.
01:35
And now we can calculate probability that this defective part was produced by c.
01:47
So that equals to the following that is probability of being produced by c and be defective so that's 0 .02 divided by 0.
02:05
Or actually let me double check it...