Question

1. The axially loaded structure shown becomes unstable and buckles when the torsion spring is no longer able to return the structure to its _____________ vertical position. (one word, 2 points) 2. A column of effective length L can be made by securely nailing together identical planks in either of the arrangements shown. For the thickness of the planks indicated, determine the ratio of the critical load using the arrangement a to the critical load using the arrangement b. (8 points) d4

          1.
The axially loaded structure shown becomes unstable and
buckles when the torsion spring is no longer able to return the
structure to its _____________ vertical position.
(one word, 2 points)
2. A column of effective length L can be made by securely nailing together identical planks in
either of the arrangements shown. For the thickness of the planks indicated, determine the ratio
of the critical load using the arrangement a to the critical load using the arrangement b. (8 points)
d4
        
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1.
The axially loaded structure shown becomes unstable and
buckles when the torsion spring is no longer able to return the
structure to its  vertical position.
(one word, 2 points)
2. A column of effective length L can be made by securely nailing together identical planks in
either of the arrangements shown. For the thickness of the planks indicated, determine the ratio
of the critical load using the arrangement a to the critical load using the arrangement b. (8 points)
d4

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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1. The axially loaded structure shown becomes unstable and buckles when the torsion spring is no longer able to return the structure to its vertical position. One word, 2 points. 2. A column of effective length L can be made by securely nailing together identical planks in either of the arrangements shown. For the thickness of the planks indicated, determine the ratio of the critical load using arrangement a to the critical load using arrangement b. 8 points. (a) (b)
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Transcript

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00:01 Hello students, let's solve this question step by step.
00:03 Here, ma can be written as equation is ma is equal to by into ab minus 1 by 2 into wl into ab into 2 by 3 into ab minus 1 by 2 into wl into bf into ab plus bf by 3 will be equal to 0.
00:46 Now, let's substitute the values into this equation.
00:49 Hence, it will be equal to by into 18 is equal to half into 400 into 18 into 2 by 3 into 18 plus 1 by 2 into 800 into 9 into 18 plus 9 by 3.
01:16 Hence, we'll get by will be equal to 9000 lb.
01:23 Now, we can write ay plus by will be equal to 1 by 2 into 800 into 18 plus 9.
01:38 Now, from here on solving for ay, we'll get, we know that by value is 9000.
01:45 Ay will be equal to 1800 lb.
01:51 Now, we can find out omega c which is equal to omega l into ac by ab.
02:01 I'll show how i get this.
02:06 So, here these are the points a and b.
02:08 Here, omega l is in this side and omega c acts in this direction.
02:14 This is how we got the relation for omega c.
02:17 So, from this, let's substitute the values that is 800 into 12 by 18.
02:24 Here, omega c is equal to 533 .334 lb per feet.
02:34 Now, the equation to find out bc is equal to 1 by 2 into omega c into ac minus ay.
02:49 Here, let's substitute the values which will be equal to 1 by 2 into 533 .334 into 12 minus 1800.
03:02 It will be equal to bc value is 1400 lb...
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