Question

4-(25) Trace Figure 2.4 (attached) and find L, R, C, and D for the next round using the following information: The message length is 8 bits: 10101011 The Key is 6 bits: 101010 The (Permuted Choice 2) is implemented by means of concatenating two of its inputs. The E-table is implemented by adding 2 bits (10) to the right side of the processed message (part of the message at this point). The S-box is implemented by means of removing 2 bit from the left side of the processed message. The permutation (P) is implemented by taking 2's complement of the message received from the S-box. Note: YOU MUST SHOW YOUR WORK STEP-BY-STEP FOR FULL CREDIT

          4-(25)
Trace Figure 2.4 (attached) and find L, R, C, and D for the next round using the following
information:
The message length is 8 bits: 10101011
The Key is 6 bits: 101010
The (Permuted Choice 2) is implemented by means of concatenating two of its inputs.
The E-table is implemented by adding 2 bits (10) to the right side of the processed message (part
of the message at this point).
The S-box is implemented by means of removing 2 bit from the left side of the processed
message.
The permutation (P) is implemented by taking 2's complement of the message received from the
S-box.
Note: YOU MUST SHOW YOUR WORK STEP-BY-STEP FOR FULL CREDIT

4-(25)
Trace Figure 2.4 (attached) and find L, R, C, and D for the next round using the following
information:
The message length is 8 bits: 10101011
The Key is 6 bits: 101010
The (Permuted Choice 2) is implemented by means of concatenating two of its inputs.
The E-table is implemented by adding 2 bits (10) to the right side of the processed message (part
of the message at this point).
The S-box is implemented by means of removing 2 bit from the left side of the processed
message.
The permutation (P) is implemented by taking 2's complement of the message received from the
S-box.
Note: YOU MUST SHOW YOUR WORK STEP-BY-STEP FOR FULL CREDIT

Added by Austin D.

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