00:01
Hello, in the question we have given that in a circuit consisting of resistor, capacitor and inductor all combined in series.
00:09
So, this resistance is given that is of 250 ohms.
00:15
Then this inductance is given that is of 0 .6 milli henries and the capacitance is given that is 0 .5 into 10 raised to minus 6 farads.
00:34
Also, we have provided the frequency that is 60 hertz and v is equals to 200 sin of actually it is written 2 i i f t.
00:51
So, we do not need this actually, we don't need this 2 i i f t whatever it is, we just need this 200.
01:00
As we will solve the problem, we will understand.
01:02
So, now in the first one, we have to find out the impedance.
01:13
Now, in order to find out the impedance, we should know the formula.
01:16
So, z is equals to square root of r square plus xc minus xl square.
01:29
We can write xl minus xc.
01:31
So, whatever it is.
01:35
So, now what is xc? xc is equals to 1 upon omega c and xl is equal to omega l.
01:45
So, we need to find out omega.
01:47
So, omega is nothing but 2 pi f.
01:50
So, it is nothing but 2 into 3 .14 into 60 and if we calculate this, so omega will turn out to be 376 .8 radian per second.
02:07
So, this is the value of omega.
02:10
Now, from here we can find out xc and xl.
02:13
So, what is xc? xc will be 1 upon omega l omega c.
02:20
So, that is 376 .8 into ce is 0 .5 into 10 raised to minus 6 and if we calculate this, so xc will turn out to be this xc will turn out to be 5312 .08.
02:46
This is ohms, but we will put it later.
02:52
So, value this inductance is given that is 0 .6 into 10 raised to 3 minus 3 because it is millihenries.
03:12
So, xl from here if we calculate, so we will get it as 226 .08 into 10 raised to minus 3.
03:23
So, basically this will be 0 .226...